PlSc 724 - Practice Exam 2 Questions
1. Assume you have ten wheat varieties and you plan a yield trial. List some of the points you should consider in choosing a design. Possible designs are CRD, RCBD, and latin square. GO TO ANSWER 1.
2. Given that t=8 and r>1, which design (CRD, RCBD, LS) has the largest and which design the least number of degrees of freedom for experimental error? GO TO ANSWER 2.
3. Tell how the randomization procedure for the CRD is different from the RCBD? GO TO ANSWER 3.
4. Fill in the following diagram with possible randomizations for a CRD and RCBD Be sure you assign treatments to the experimental units in such a way that the CRD cannot be mistaken for a RCBD. T=5, r=3. GO TO ANSWER 4.
CRD
RCBD
5. In a RCBD, what is the purpose of grouping treatments into blocks? GO TO ANSWER 5. 6. In a RCBD, is it most desirable to have variation between or within blocks? GO TO ANSWER 6.
7. Given an RCBD with sampling, what is the cause of sampling error? GO TO ANSWER 7. 8. What precisely, contributes to sampling error sum of squares? GO TO ANSWER 8.
9. Define experimental error for the RCBD. GO TO ANSWER 9.
10. Write the linear additive model for the RCBD, and then define each term. GO TO ANSWER 10.
11. What should you conclude if you find that the F-test for replications is significant in an RCBD? GO TO ANSWER 11.
12. Assume you have an RCBD with t=8 and r=3. If F for treatments is significant at the .05 level, what can you conclude? What additional statistical procedure would be informative? GO TO ANSWER 12.
13. Assume you have an RCBD in which you have six treatments and four replications. Data from two experimental units are missing. GO TO ANSWER 13.
A) List the procedure you would follow to obtain estimates of the missing data.
B) How many degrees of freedom would you have for error?
14. The formula to calculate an estimate for a missing plot for an RCBD is:
(rB + tT - G)/(r - 1)(t - 1). Define each term in the numerator. GO TO ANSWER 14.
15. Assume you have an RCBD and have ten treatments with four reps. If treatment `A` is repeated three times within each rep., show the degrees of freedom for the sources of variation making up experimental error. GO TO ANSWER 15.
16. Assume five treatments and four replications of an RCBD and treatment two is repeated twice in every block and treatment five is repeated three times in every block. List all the sources of variation and their degrees of freedom. Show possible randomizations of replications one and two. GO TO ANSWER 16.
17. Assume you have 6 treatments and 3 replications in an RCBD. Treatments 1 and 2 repeated two times in each replication. List the randomization procedure and then show how the procedure is used to do the randomization. GO TO ANSWER 17.
18. A) given the following data, compute treatment sums of squares GO TO ANSWER 18.
T1 | T1 | T2 | T3 | T4 | T5 | Y.j | |
R1 | 36 | 34 | 46 | 38 | 52 | 57 | 263 |
R2 | 42 | 43 | 50 | 47 | 53 | 51 | 286 |
R3 | 45 | 49 | 52 | 44 | 61 | 64 | 315 |
Yi. | 123 | 126 | 148 | 129 | 166 | 172 | 864 |
B) How many degrees of freedom are there for treatments, experimental error, and t1/reps?
C) Calculate the standard error of a difference appropriate for comparing treatments one and four, assuming the error mean square is 722.
19. Given the following data:
T1 | T2 | T3 | T4 | T5 | T6 | Y.j | |
R1 | 50 | 68 | 28 | 32 | 20 | 17 | 215 |
R2 | 62 | 74 | 36 | 34 | 30 | 29 | 265 |
R3 | 75 | 93 | 49 | 53 | 37 | 40 | 347 |
Yi. | 187 | 235 | 113 | 119 | 87 | 86 | 827 |
A) Compute treatment SS, assuming a normal RCBD.
B) Compute treatment SS, assuming an RCBD with T3=T4 and T5=T6, that is, two treatments are each repeated twice in each replication.
C) Compute `T5=T6/reps` SS (same assumption as part b).
D) How many degrees of freedom would you have for the source of variation listed in part C?
E) Continuing the conditions stated in part B, assume experimental error SS equals 55.56,
compute the standard error you would need to compare T1 with T3=T4.
20. From the following analysis of variance table, compute the mean square error and an estimate of sigma square epsilon. GO TO ANSWER 20
SOV | df | SS |
Replication | 3 | 237 |
Treatments | 11 | 594 |
Experimental Error | 33 | 627 |
Sampling Error | 96 | 672 |
21. Assume an RCBD and you calculate the LSD and Duncan`s mrt at the 95% level of significance. If the LSD was 11.5, would the LSR value for p=2 be larger, equal, or smaller? GO TO ANSWER 21.
22. Assume you have an RCBD with six treatments and four replications, but treatment one is repeated three times within each replication. GO TO ANSWER 22.
A) Show symbolically how to calculate treatment sums of squares. Use actual numbers for the denominators.
B) Show, in detail, how to calculate an lsd comparing treatment one with treatment 3. How many degrees of freedom would be associated with the `t` value?
23. Given an RCBD with 8 treatments and 4 replications, assume you have two missing plots, one in treatment 4 rep 2, and one in treatment 7 rep 4. What are the degrees of freedom for treatments and for experimental error? GO TO ANSWER 23.
24. Given the following information, list the degrees of freedom for the indicated sources of variation. GO TO ANSWER 24.
RCBD, t=12, r=4 | Latin square |
T1 repeated 3 times per rep | r=5, 3 latin squares |
T1 within reps | Square x Treatment |
Experimental Error | Experimental Error |
25. What is the normal range in size for latin square? GO TO ANSWER 25.
26. What is the main disadvantage of a) small numbers of treatments in a latin square and b) large numbers of treatments in a latin square. GO TO ANSWER 26.
27. What is the minimum size latin square on which a complete analysis can be obtained. GO TO ANSWER 27.
28. Why are 3x3 latin squares seldom used? GO TO ANSWER 28.
29. If you were conducting an experiment with 20 treatments, what would be the biggest disadvantage of using a latin square? GO TO ANSWER 29.
30. Assume a 6x6 latin square. If you have data missing for two experimental units, how many degrees of freedom do you have for treatments and for error? GO TO ANSWER 30.
31. Diagram three different 4x4 standard latin squares. GO TO ANSWER 31.
32. List the sources of variation and degrees of freedom for the combined analysis of 3, 4x4 latin squares. GO TO ANSWER 32.
33. Tell (or illustrate) precisely how to compute the treatment SS and treatment x square ss if you have two 4x4 latin squares. GO TO ANSWER 33.
34. A latin square design has 50 degrees of freedom for sampling error and 74 degrees of freedom for total. How many degrees of freedom would you have for experimental error? GO TO ANSWER 34.
35. How many degrees of freedom are there for exp. Error in a 7x7 latin square? GO TO ANSWER 35.
36. Diagram a standard 4x4 latin square and show how to randomize it. Explain randomization procedure. GO TO ANSWER 36.
37. Use the following data to compute 1) SS A), 2) SS B and 3) SS AxB. GO TO ANSWER 37.
R1 | R2 | |
a0b0c0 | 7 | 9 |
a0b0c1 | 12 | 11 |
a0b1c0 | 13 | 16 |
a0b1c1 | 18 | 20 |
a1b0c0 | 15 | 19 |
a1b0c1 | 22 | 20 |
a1b1c0 | 24 | 27 |
a1b1c1 | 33 | 29 |
38. What is the difference, if any, between a 3 to the fourth power factorial and a 3 x 4 factorial? GO TO ANSWER 38.
39. Assume you have a 2 to the third power factorial, with treatments arranged in a latin square. What would be the size of the latin square? GO TO ANSWER 39.
40. Assume you have a 3 x 4 factorial in a RCBD with 5 blocks. Factor A is fixed and B is random. Show how to compute the variance of a treatment mean for A, B, and AB. Use actual numbers for the denominators. GO TO ANSWER 40.
41. Assume you have an RCBD with a 2 to the third power factorial arrangement. GO TO ANSWER 41.
A)Write the expected mean square for B if A and B are fixed and C is random. B) What mean square would be the appropriate denominator in making an F-test for B? 42. Assume you apply a herbicide (rates of 4, 8, and 12 ounces per acre) to each of six wheat varieties using a CRD with r=4, a 3 x 6 factorial arrangement. List all sources of variation and degrees of freedom. GO TO ANSWER 42.
43. Indicate the degrees of freedom for all error terms given the following conditions (R=4, A=5, B=2, C=3): RCBD GO TO ANSWER 43.
A) Factorial
B) Given situation A, what is the formula for the standard error between two B means, assuming all factors are fixed. Use numbers where possible.
44. Write the expected mean square for C assuming A and C are fixed variables and B is a random variable. GO TO ANSWER 44.
45. What would be the appropriate denominator to make an F-test of C, given the conditions of question 44? GO TO ANSWER 45.
46. Write the expected mean square for B, if A is random and B and C are fixed. GO TO ANSWER 46.
47. Given 3 factors, A, B, and C, write the expected mean square for B if A and B are random and C is fixed. GO TO ANSWER 47.
48. Write the expected mean square for AxD, assuming a four factor factorial with A and B fixed, and C and D random. What term would be the denominator of an F-test of the AxD mean square? GO TO ANSWER 48.
49. Given the following table of treatment totals, r=5, compute the main effect of A and the effect of AxB. GO TO ANSWER 49.
a1 | a2 | |
b1 | 25 | 50 |
b2 | 40 | 80 |
50. From the following table of treatment means, compute the simple effects of A, simple effects of B, main effect of A, main effect of B, and interaction effect. Label each answer. GO TO ANSWER 50.
a1 | a2 | |
b1 | 60 | 65 |
b2 | 70 | 100 |
PlSc 724 - Answers to Exam 2 Practice Questions
ANSWER 1 ANSWER 2 ANSWER 3
RCBD - each replicate is grouped into a block and treatments are randomized within each
replicate.
ANSWER 4.
A | B | C | A | D |
D | C | D | B | E |
E | A | E | B | C |
RCBD
C | A | D | B | E |
A | E | B | C | D |
C | B | E | A | D |
ANSWER 5
. To keep the variability among experimental units within a block as small as possible and to maximize differences among blocks. This design contributes to increased precision by detecting treatment differences.ANSWER 6
. BetweenANSWER 7
. Sampling error is due to a failure of sample observations to be the same within experimental units.ANSWER 8
. SS Sampling Error = SS total - SS among Expt. Unit Total.ANSWER 9
. Experimental error is due to the failure of treatment observations to have the same relative rank in all replicates.ANSWER 10.
Yij=µ +i+ j +ijµ estimated by Y.. bar
i estimated by Yi. bar - Y.. bar
j estimated by Y.j bar - Y.. bar
ij estimated by Yij - Yi. bar + Y.j bar + Y.. bar
ANSWER 11. ANSWER 12. ANSWER 13.
(Yi. bar+ Y.j bar)/2
ii. The missing plot equation then is used to estimate the final plot.
iii. Using the number calculated in part ii, estimate the other missing value using the formula presented above.
iv. Keep doing part ii and iii until the estimated values stay the same.
b) 13
ANSWER 14.
B = block total containing missing plot
t = number of treatments
T = treatment total containing missing plot
G = Grand total
ANSWER 15
SOV | df |
Rep | 3 |
Trt | 9 |
Check(Rep) | 8 |
Error | 27 |
Total | 47 |
ANSWER 16.
SOV | df |
Rep | 3 |
Trt | 4 |
Check2(Rep) | 4 |
Check5(Rep) | 8 |
Error | 12 |
Total | 31 |
Randomization example
Rep 1 T1 T4 T2 T5 T2 T5 T3 T5
Rep 2 T2 T2 T4 T1 T5 T3 T5 T5
ANSWER 17 ANSWER 18.
b) 4,8,3
c) 19
ANSWER 19.
b) 6027.44
c) 9.50
d) 3
e) 2.15
ANSWER 20
Estimate of sigma square epsilon = 3
ANSWER 21. ANSWER 22
Y 1.2/12 + Y 2.2/4 + ... + Y 6.2/4 - Y2../32
b) lsd =s D bar x t
where s D bar = Error MS[(12 + 4)/(12 x 4)]
df =15
ANSWER 23
Error df = 19
ANSWER 24
Exp. Error = 33 Exp. Error = 36
ANSWER 25. ANSWER 26
b) Cost
ANSWER 27 ANSWER 28. ANSWER 29. ANSWER 30
Error = 18
ANSWER 31
A | B | C | D |
B | C | D | A |
C | D | A | B |
D | A | B | C |
2)
A | B | C | D |
B | A | D | C |
C | D | A | B |
D | C | A | B |
3)
A | B | C | D |
B | D | A | C |
C | A | D | B |
D | C | A | B |
ANSWER 32.
SOV | df |
Square | 2 |
Row(Square) | 9 |
Column(Square) | 9 |
Treatment | 3 |
Square x Treatment | 6 |
Error | 18 |
Total | 47 |
ANSWER 33.
T1 | T2 | T3 | T4 | Y.j | |
Square 1 | 10 | 20 | 30 | 40 | 100 |
Square 2 | 20 | 30 | 40 | 50 | 140 |
Yi. | 30 | 50 | 70 | 90 | 240 |
Trt SS = (302 + ... + 902 )/8 - 2402/32
Sq x Trt SS = (102 + ... + 502 )/4 - CF - Sq SS - TRT SS
ANSWER 34. ANSWER 35. ANSWER 36.
ii) Randomize all columns
iii) Randomize all but first row
ANSWER 37
b) SS B = 264.0625
c) SS A x B = 5.0625
ANSWER 38 ANSWER 39 ANSWER 40
Variance of a treatment mean for B = Error MS/(5x3)
Variance of a treatment mean for AxB = Error MS/(5)
ANSWER 41.
b) Use estimated mean square for BC. BC = 2 + ra2 BC.
ANSWER 42
SOV | df |
Variety | 5 |
Rate | 2 |
Variety x Rate | 10 |
Error | 54 |
Total | 71 |
ANSWER 43
. a) 87b) [(2 x Error MS)/(4x5x3)]1/2
ANSWER 44. ANSWER 45. ANSWER 46. ANSWER 47. ANSWER 48.
denominator would be the ACD EMS
ANSWER 49.
Interaction = 1.5
ANSWER 50
Simple effect of A at b2 = 30
Main effect of A = 22.5
Simple effect of B at a1 = 10
Simple effect of B at a2 = 25
Main effect of B = 17.5
Interaction = 7.5