Genetic Linkage

Calculating Interference Values From The Example

• v - ct - 0.132 recombination frequency
• ct - cv - 0.064 recombination frequency

Expected double crossover frequency equal the product of the two single crossover frequency

• expected double crossover frequency = 0.132 x 0.064 = 0.0084
• Total double crossovers = 1448 x 0.0084 = 12
• Observed double crossovers = 8
• c.o.c = 8/12

I for example = 100 x [1 -(8/12)] = 33%

• Most often I is between 0 and 1 indicating positive interference
• Occasionally I is greater than 1 indicating negative interference